Introduction

Prefix to Infix conversion means converting a mathematical expression from prefix notation into infix notation.

Prefix notation:

 +AB

Infix notation:

 A+B

In prefix notation:

  • operators are written before operands

In infix notation:

  • operators are written between operands

Example:

Input: *+ABCOutput: ((A+B)*C)

Explanation:

  • +AB becomes (A+B)
  • then multiplied with C

Constraints

Expression contains:Operands:
A-Z, a-z, 0-9

Operators:
+, -, *, /, ^

Approach 1 : Brute Force (Manual Expression Building)

Explanations:

Explanation:

The idea is to manually combine operators and operands.

Steps:

  1. Traverse prefix expression.
  2. Detect operators.
  3. Combine operands manually.
  4. Build infix expression.

This approach becomes difficult for:

  • nested expressions
  • large expressions
  • precedence handling

So stack-based conversion is preferred.

Dry Run

Input:*+ABC

Traversal from right:
C → operand
B → operand
A → operand

+ → combine:
(A+B)

* → combine:
((A+B)*C)
Final Output:
((A+B)*C)

Practice :

Complexity Analysis :

Time Complexity:- O(n)Explanation :
Expression is traversed once.
Space Complexity:- O(n)
Explanation :
Stack stores intermediate expressions.

Approach 2 : Optimal Solution(Using Stack)

Explanations:

Explanation:

This is the most optimized and interview-preferred solution.

The idea is:

  • traverse expression from right to left
  • push operands into stack
  • when operator appears:
    • pop two operands
    • combine expression
    • push back into stack

At the end:

  • stack contains final infix expression

This efficiently converts prefix expressions into infix expressions.

Dry Run

Input:*+ABC

Step 1:
Push C
Stack:
[C]
Step 2:
Push B
Stack:
[C, B]
Step 3:
Push A
Stack:
[C, B, A]
Step 4:
+ operator
(A+B)
Stack:
[C, (A+B)]
Step 5:
* operator
((A+B)*C)
Final Output:
((A+B)*C)

Practice :

Complexity Analysis :

Time Complexity:- O(n)Explanation :
Each character is processed only once.
Space Complexity:- O(n)
Explanation :
Stack stores intermediate expressions.

Why This Problem is Important

This problem builds the foundation for:

  • Expression parsing
  • Compiler design
  • Stack applications
  • Expression tree construction
  • Mathematical expression handling

Real-World Applications

Prefix to Infix conversion is used in:

  • Compilers
  • Expression parsers
  • Mathematical software
  • Programming language interpreters
  • Calculator engines

Common Beginner Mistakes

  • Incorrect operand order
  • Traversing in wrong direction
  • Missing parentheses
  • Improper stack handling
  • Not combining expressions correctly

Interview Tip

Interviewers often expect:

  • correct traversal direction
  • proper stack usage
  • operand handling logic
  • O(n) solution

Always explain:

  • why prefix is processed from right to left
  • why stack simplifies expression construction

Related Questions

  • Infix to Postfix
  • Evaluate Postfix Expression
  • Basic Calculator
  • Valid Parentheses
  • Expression Tree Evaluation

Final Takeaway

The Prefix to Infix problem is one of the most important stack-based expression conversion problems.

It teaches:

  • stack processing
  • expression parsing
  • operand handling
  • expression construction

Understanding this problem builds a strong foundation for:

  • compiler design
  • parser implementation
  • advanced stack interview problems.