Introduction
Longest Increasing Subsequence (LIS) is one of the most important Dynamic Programming interview questions.
You are given:
nums[] Goal:
Find the length of the longest strictly increasing subsequence.A subsequence:
Find the length of the longest strictly increasing subsequence. Example
nums = [10,9,2,5,3,7,101,18] Output:
4Explanation:
LIS = [2,3,7,101]Length = 4
Key Observation
For every element:
Try extending all previous increasing subsequences. Recurrence:
dp[i] = 1 + max(dp[j])
where: j < i and nums[j] < nums[i]
Approach 1 : Memoization
Explanation
For each index:
- Take current number.
- Compare with previous number.
- Extend increasing sequence.
- Store results.
- Reuse computations.
Approach 2 : Tabulation
Explanation
State:
dp[i] = Length of LIS ending at index i Transition:
If nums[j] < nums[i]
dp[i] = max(dp[i],dp[j] + 1)
Dry Run
Input:
[10,9,2,5,3,7,101,18] DP Array:
[1,1,1,2,2,3,4,4] Answer:
4 Subsequence:
[2,3,7,101]Approach 3 : Binary Search Optimization
Explanation
Instead of checking all previous elements:
Maintain a tails array. Idea:
tails[i] = Smallest possible tail for an increasing subsequence of length i+1. Use Binary Search to place elements.
Practice
Complexity Analysis
Memoization
Time Complexity: O(n²)
Space Complexity: O(n²)
Tabulation
Time Complexity: O(n²)
Space Complexity: O(n)
Binary Search Optimization
Time Complexity: O(n log n)Space Complexity: O(n)
Why This Problem is Important
- Sequence Dynamic Programming
- Binary Search Optimization
- State Transitions
- Longest Subsequence Problems
- Foundation for Advanced LIS Variants
Common Beginner Mistakes
- Confusing subsequence with subarray
- Using <= instead of <
- Incorrect binary search implementation
- Wrong DP state definition
- Forgetting strict increasing condition
Interview Tip
Always explain:
dp[i] = Length of LIS ending at iThen mention:
Optimized solution uses Binary Search with tails array. This often impresses interviewers.
Related Questions
- Number of LIS
- Russian Doll Envelopes
- Longest Bitonic Subsequence
- Largest Divisible Subset
- Maximum Length Pair Chain
Final Takeaway
Longest Increasing Subsequence is one of the most important Dynamic Programming problems.
It teaches:
- Sequence DP
- State Design
- Binary Search Optimization
- Subsequence Problems
- Advanced DP Thinking
Mastering LIS provides the foundation for many advanced sequence and optimization interview questions.